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 程式師世界 >> 編程語言 >> 更多編程語言 >> 編程綜合問答 >> httpget-HttpGet拋出異常,不明白!求指導~

httpget-HttpGet拋出異常,不明白!求指導~

編輯:編程綜合問答
HttpGet拋出異常,不明白!求指導~

想用數據庫做一個登錄驗證的功能,服務器端響應正常,json數據包 {"ret":1,"num":123}
ret是登錄正常時的狀態值,num是號碼:123
url是192.168.1.3:8080/web/getActInfo
params:num=123
通過logcat發現在httpGet中拋出了一個異常,但是搞不明白!!痛苦了一下午求點撥!

public String httpGet(String url, String params) throws Exception
{
String response = null;
if (null!=params&&!params.equals(""))
{

        url += "?" + params;
    }

    int timeoutConnection = 8000;  
    int timeoutSocket = 10000;  
    HttpParams httpParameters = new BasicHttpParams();// Set the timeout in milliseconds until a connection is established.  
    HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);// Set the default socket timeout (SO_TIMEOUT) // in milliseconds which is the timeout for waiting for data.  
    HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);  

    HttpClient httpClient = new DefaultHttpClient(httpParameters);  
    HttpGet httpGet = new HttpGet(url);
    try
    {
        HttpResponse httpResponse = httpClient.execute(httpGet);
        int statusCode = httpResponse.getStatusLine().getStatusCode();
        if (statusCode == HttpStatus.SC_OK) //SC_OK = 200
        {
            response = EntityUtils.toString(httpResponse.getEntity());
        }
        else
        {
            response = "狀態碼"+statusCode;
        }
    } catch (Exception e)
    {
        throw new Exception(e);         
    } 

最佳回答:


網絡連接問題,服務器無響應

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