Daily question -1108 IP address invalidation_ Python

• Give you an effective IPv4 Address address, Go back to this IP Invalid version of address .

• The so-called invalidation IP Address , In fact, it is to use “[.]” Instead of every “.”.

Example 1：

Input ：address = “1.1.1.1”
Output ：“1[.]1[.]1[.]1”

Example 2：

Input ：address = “255.100.50.0”
Output ：“255[.]100[.]50[.]0”

Tips ：

• Given address Is an effective IPv4 Address

Program code

class Solution:
def defangIPaddr(self, address: str) -> str:
ans = ''
for i in address:
if i == '.':
ans += '[.]'
else:
ans += i
return ans