hibernate 4.3
使用hibernate4.3的時候獲取SessionFactory和之前不一樣,網上看到一篇(StackOverFlow裡面的),可以使用下面的方式:
package util.hibernate;
import org.hibernate.HibernateException;
import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.boot.registry.StandardServiceRegistry;
import org.hibernate.boot.registry.StandardServiceRegistryBuilder;
import org.hibernate.cfg.Configuration;
public class HibernateUtil {
private static SessionFactory factory;
static{
try {
Configuration configuration = new Configuration().configure();
StandardServiceRegistry serviceRegistry = new StandardServiceRegistryBuilder().applySettings(configuration.getProperties()).build();
factory = configuration.configure().buildSessionFactory(serviceRegistry);
} catch (HibernateException e) {
e.printStackTrace();
}
}
public static SessionFactory getSessionFactory(){
return factory;
}
public static Session getOpenSession(){
return factory.openSession();
}
public static Session getCurrentSession(){
return factory.getCurrentSession();
}
public static void closeSession(Session session){
if(session!=null){
if(session.isOpen()){
session.close();
}
}
}
}
使用StandardServiceRegister類來初始化我們的SessionFactory。
查看本欄目
但是在使用注解的時候,卻出現了下面的錯誤:
java.lang.NoSuchMethodError: javax.persistence.Table.indexes()[Ljavax/persistence/Index;
at org.hibernate.cfg.annotations.EntityBinder.processComplementaryTableDefinitions(EntityBinder.java:936)
at org.hibernate.cfg.AnnotationBinder.bindClass(AnnotationBinder.java:781)
at org.hibernate.cfg.Configuration$MetadataSourceQueue.processAnnotatedClassesQueue(Configuration.java:3762)
at org.hibernate.cfg.Configuration$MetadataSourceQueue.processMetadata(Configuration.java:3716)
at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1410)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1844)
at util.hibernate.HibernateUtil.<clinit>(HibernateUtil.java:17)
at HibernateTest.testSave(HibernateTest.java:24)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:606)
at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44)
at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15)
at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41)
at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:20)
at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:28)
at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:31)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:73)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:46)
at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:180)
at org.junit.runners.ParentRunner.access$000(ParentRunner.java:41)
at org.junit.runners.ParentRunner$1.evaluate(ParentRunner.java:173)
at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:28)
at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:31)
at org.junit.runners.ParentRunner.run(ParentRunner.java:220)
at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:50)
at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197)
結果搞了好久都沒搞定,但是我之前用4.3 的是可以的,怎麼回事?
通過對比,我發現在model類中如果使用了Table(name="t_user"),就會報這樣的錯誤,但是如果我寫成@Entity(name="t_user")這樣就沒問題了,這個可能是Hibernate4.3的一個bug?這就不得而知了,不過如果用4.3 的話,那麼直接使用Entity來指定表名就可以解決這個問題了。