UVA 10069 Distinct Subsequences（DP)

UVA 10069 Distinct Subsequences（DP)

考慮兩個字符串，我們用dp[i][j]表示字串第到i個和字符串到第j個的總數，因為字串必須連續

因此dp[i][j]可以有dp[i][j-1]和dp[i-1][j-1]遞推而來，而不能由dp[i-1][j]遞推而來。而後者的條件

是字串的第i個和字符串相等。

A subsequence of a given sequence is just the given sequence with some elements (possibly none) left out. Formally, given a sequence X =x₁x₂…x_m, another sequence Z = z₁z₂…z_k is a subsequence of X if there exists a strictly increasing sequence <i₁, i₂, …, i_k> of indices of Xsuch that for all j = 1, 2, …, k, we have x_ij = z_j. For example, Z = bcdb is a subsequence of X = abcbdab with corresponding index sequence< 2, 3, 5, 7 >.

In this problem your job is to write a program that counts the number of occurrences of Z in X as a subsequence such that each has a distinct index sequence.

Input

The first line of the input contains an integer N indicating the number of test cases to follow.

The first line of each test case contains a string X, composed entirely of lowercase alphabetic characters and having length no greater than 10,000. The second line contains another string Z having length no greater than 100 and also composed of only lowercase alphabetic characters. Be assured that neither Z nor any prefix or suffix of Z will have more than 10¹⁰⁰ distinct occurrences in X as a subsequence.

Output

For each test case in the input output the number of distinct occurrences of Z in X as a subsequence. Output for each input set must be on a separate line.

Sample Input

Sample Output

import java.io.*;
import java.math.*;
import java.util.*;
public class Main{
	  public static void main(String []args){
		  Scanner cin=new Scanner(System.in);
		  int t=cin.nextInt();
		  while(t--!=0){
			  char a[]=cin.next().toCharArray();
			  char b[]=cin.next().toCharArray();
//			  System.out.println("2333  ");
			  BigInteger [][] dp=new BigInteger[110][10100];
			  for(int i=0;i