Here's a small problem , I always set it up websocket Links are 127.0.0.1:8000, Then it reports an error and cannot be connected socket, Just know this link is to be able to directly access , and URL equally , It is not used internally by the server IP, So use window.location.host As address
<script type="application/javascript">
//terminal
var socket = new WebSocket("ws://"+window.location.host+"/console/ws_console/");
// Trigger after creating the connection
socket.onopen = function (event) {
socket.send('balabal');
}
// When websocket Accept the information sent by the server This function will be triggered automatically
socket.onmessage = function (event){
console.log(' received '+event.data);
}
function sendMessage(){
let tag = document.getElementById("txt");
socket.send(tag.value);
}
function closeConn() {
socket.close(); // The server sends a disconnect request
}
</script>
Inside app All are console, It's just a random one app
Install it.
pip3 install dwebsocket
Configure it app
INSTALLED_APPS = [
......
'dwebsocket',
]
Configure the routing urls.py
urlpatterns = [
......
url(r'^ws_console/$',views.wsConsole),
]
Configure view file views.py
Both of the decorators here can be used , But if you use require Words , May affect normal HTTP request
from dwebsocket.decorators import accept_websocket
from dwebsocket import require_websocket
@require_websocket
def wsConsole(request):
if request.is_websocket():
WS=request.websocket
message = WS.wait()
print(message.decode('utf-8'))
WS.send(message)
Several commonly used websocket Method
request.is_websocket（）： Determine if the request is websocket The way , Is to return true, Otherwise return to false
request.websocket： When the request is websocket When , Will be in request Add one websocket attribute ,
WebSocket.wait（） Return a message sent by the client , Failure to receive a message will result in congestion
WebSocket.read（） and wait You can also accept the returned message , But this is non blocking , No message returned None
WebSocket.count_messages（） Number of returned messages
WebSocket.has_messages（） Return whether there is a new message
WebSocket.send（message） Send messages like clients ,message by byte type
Then enter the page , stay console There will be output in it , At the same time, there will be such an error , It is possible that the above operation is one-off , After the execution, the link is broken
(index):361 WebSocket connection to ‘ws://192.168.1.110:8000/console/ws_console/’ failed: Invalid frame header
If continuous input is required , First, modify the front end , Let's turn it into three buttons first , Connect 、 Send and disconnect . At the same time, the returned content will be displayed in p In the label
The front-end code
// Control
<div>
<input type="text" placeholder=" Please enter " id="text">
<input type="button" value=" send out " onclick="sendMessage()">
<input type="button" value=" close " onclick="closeSocket()">
<input type="button" value=" link " onclick="connectSocket()">
<p id="result-text">sss</p>
</div>
//script
<script type="application/javascript">
//var socket = new WebSocket("ws://"+window.location.host+"/console/ws_console/");
// Trigger after creating the connection
function connectSocket(){
if (window.socket){
alert(" Link established ");
return ;
}
var socket = new WebSocket("ws://"+window.location.host+"/console/ws_console/");
socket.onopen = function (event) {
socket.send('balabal');
}
socket.onmessage = function (event){
console.log(' received '+event.data);
}
window.socket=socket;
}
// When websocket Accept the information sent by the server This function will be triggered automatically
function sendMessage(){
if (!window.socket){
alert(" No connection established , Unable to send ");
}
socket.send($("#text").val());
}
function closeSocket() {
if (window.socket){
window.socket.close();
console.log(" Closed successfully ");
}
}
</script>
Modify the backend views.py Code for
It is equivalent to polling all the time , Receive the content from the front end , As bash Command execution , Return the result , On display in p In the label
import subprocess
@require_websocket
def wsConsole(request):
if request.is_websocket():
for message in request.websocket:
# Judge whether to turn off
if not message:
print(' Shut down the ')
else:
Command=message.decode('utf-8')
print(Command)
Result=subprocess.getoutput(Command)
request.websocket.send(Result.encode('utf-8'))
